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产品系列: 波纹管补偿器

参考价格:1 | 发布于:2009-9-13

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产品信息
产品名称:铰链波纹补偿器
产品品牌:普惠
规格型号:DN65-DN5000
生产厂家:河北普惠机电设备有限公司
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                                                 铰链波纹补偿器(JY) 
                                             
                                             
                                                  
                                                 
                                             
                                             
                                                  铰链波纹补偿器用途:  
                                             
                                             
                                                 铰链波纹补偿器适用于角位移的补偿 
                                             
                                             
                                                   
                                             
                                             
                                                  铰链波纹补偿器型号:  
                                             
                                             
                                                 本厂生产DN65-DN5000,压力级别0.1Mpa-2.5Mpa 
                                             
                                             
                                                   
                                             
                                             
                                                  铰链波纹补偿器连接方式:  
                                             
                                             
                                                 1、法兰连接 2、接管连接 
                                             
                                             
                                                   
                                             
                                             
                                                  铰链波纹补偿器产品角向补偿量:  
                                             
                                             
                                                 ±4度-±9度 
                                             
                                         
                                     
                                     
                                 
                             
                         
                         
                             
                                 
                                     
                                       
                                     
                                 
                                 
                                      二、铰链波纹补偿器应用举例:  
                                 
                                 
                                     
                                       某热管安装温度:20℃,通径500,工作压力0.6MPa(6kgf/cm2),最低温度-10℃,碳钢管线膨胀系数a=13.2×10ˉ6/℃。 
                                     
                                 
                                 
                                       就如下管路安装形式设计计算: 
                                 
                                 
                                     
                                       
                                     
                                 
                                 
                                     1、确定位移量: 
                                     
                                    △X=al△T=13.2×10ˉ6(80+80)×103×(120-(-10°))=275mm 
                                     
                                    2、选用补偿器: 
                                    补偿器Ⅰ选用:0.6JY500×6J,θ0=±8°(额定位移2×8°) 
                                    LⅠ=1.1m,KθⅠ=197N&|m i d|dot;m 
                                    补偿器Ⅱ、Ⅲ选用:0.6JY500×4,θ0=±5° 
                                    LⅡ=LⅢ=0.9m,KθⅡ=KθⅢ=295N&|m i d|dot;m/度 
                                      
                                 
                                 
                                     
                                       
                                     
                                 
                                 
                                     即LA(必须大于等于)≥997.69mm……(1) 
                                    一般Lp≥1.5DN×4+LⅠ+LⅡ+LⅢ……(2) 
                                    (Lp为补偿段安装长度) 
                                    根据(1)式,取一定余量,将LA值向上圆整: 
                                    LA=1200
                                     (在安装跨距要求允许条件下,LA适当大一点好) 
                                    实际工作角位移 
                                     
                                 
                                 
                                     
                                       
                                     
                                 
                                 
                                     3、考虑冷紧问题: 
                                     
                                    为了改善管路受力状总况,设计安装时通常对补偿器进行冷紧。冷紧量按以下公式计算: 
                                 
                                 
                                     
                                       
                                     
                                 
                                 
                                     所以沿工作位移相反方向进行冷紧安装(冷紧量δ=74.04mm) 
                                     
                                    4、计算支座承受载荷: 
                                     
                                    下面分析固定支座G1、G2和导向支架D1、D2的受力情况。 
                                    a、膨胀节变形力矩。 
                                 
                                 
                                     
                                       
                                     
                                 
                                 
                                     b、 G1点:                       D1点: 
                                    Fy=Fz=0                      Fx=Fy=Fz=0,Mx=My=0  
                                    Fx=-V=-1899N                    Mz=MⅡ=973.5N&|m i d|dot;m 
                                    Mx=My=Mz=0  
                                    G2: 
                                    Fx=V=1899N                  D2:Fx=Fy=Fz=0,Mx=My=0 
                                    Fy=Fz=0,Mx=My=Mz=0               Mz=-MⅡ=-973.5N&|m i d|dot;m 
                                    受力图: 
                                 
                                 
                                     
                                       
                                     
                                 
                                 
                                     
                                       
                                     
                                 
                                 
                                     1、确定位移: 
                                 
                                 
                                     
                                       
                                     
                                 
                                 
                                     2、选用补偿器: 
                                    补偿器Ⅰ选用:0.6JY500×2,θ0=±2.5 
                                    LⅠ=0.8m,KθⅠ=590N&|m i d|dot;m/度 
                                    补偿器Ⅱ、Ⅲ选用:0.6JY500×6,θ0=±8 
                                    LⅡ=LⅢ=1.1m,KθⅡ=197N&|m i d|dot;m/度 
                                 
                                 
                                     
                                       
                                     
                                 
                                 
                                     一般B值根据补偿器Ⅲ的长度LⅡ和管路弯曲半径大小取值,比如取为1m,A值安装跨距要求允许下,按式(1)取大一点,如A=2m 
                                 
                                 
                                     
                                       
                                     
                                 
                                 
                                     按(2)式向上调整C值(适当大一点好):  
                                     C=1600=1.6m 
                                    即: 
                                      
                                 
                                 
                                     
                                       
                                     
                                 
                                 
                                     根据LⅠ、LⅡ、LⅢ,A、B、C值即可确定补偿器的安装位置。 
                                 
                                 
                                       
                                 
                                 
                                     3、考虑冷紧问题 
                                 
                                 
                                     
                                       
                                     
                                 
                                 
                                     沿工作位移相反方向进行冷紧安装。
                                     4、计算支座承受载荷: 
                                    a、膨胀节变形力矩: 
                                     
                                 
                                 
                                     
                                       
                                     
                                 
                                 
                                     膨胀节横向反力: 
                                 
                                 
                                     
                                       
                                     
                                 
                                 
                                     b、G1点: 
                                    Fx=-V1=-1660.37N 
                                    Fy=Fz=0 
                                    Mx=My=Mz=0 
                                    D1点: 
                                    Fx=Fz=0,Mx=My=0 
                                    Fy=V2=1661.31N 
                                    M2=-MⅡ+V2×L′-V1(20-B-C) 
                                    =-1280.55+1661.31×2-1660.37(20-1.0-1.6) 
                                    =-26848.37(N&|m i d|dot;m) 
                                    D2点: 
                                    Fx=Fz=0,Mx=My=0 
                                    Fy=-V2=-1661.31(N)
                                          Mz=MⅠ-Fy(2+LⅠ/2)=286.2+1661.31(2+0.8/2)=4273.34(Nm) 
                                     受力图: 
                                     
                                 
                                 
                                     
                                       
                                     
                                 
                                 
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